Open Journal of Discrete Mathematics
Vol. 2 No. 1 (2012) , Article ID: 17156 , 3 pages DOI:10.4236/ojdm.2012.21005
On Cycle Related Graphs with Constant Metric Dimension
1Department of Mathematics, FAST-National University of Computer and Emerging Sciences, Peshawar, Pakistan
2Centre for Advanced Studies in Pure and Applied Mathematics, Bahauddin Zakariya University, Multan, Pakistan
Email: *gohar.ali@nu.edu.pk
Received September 16, 2011; revised November 2, 2011; accepted December 7, 2011
Keywords: Metric dimension; basis; resolving set; dragon graph
ABSTRACT
If is a connected graph, the distance
between two vertices
is the length of a shortest path between them. Let
be an ordered set of vertices of
and let
be a vertex of
. The representation
of
with respect to
is the
-tuple
. If distinct vertices of
have distinct representations with respect to
, then
is called a resolving set or locating set for
. A resolving set of minimum cardinality is called a basis for
and this cardinality is the metric dimension of
, denoted by
. A family
of connected graphs is a family with constant metric dimension if
is finite and does not depend upon the choice of
in
. In this paper, we show that dragon graph denoted by
and the graph obtained from prism denoted by
have constant metric dimension.
1. Notation and Preliminary Results
If is a connected graph, the distance
between two vertices
is the length of a shortest path between them. Let
be an ordered set of vertices of
and let
be a vertex of
. The representation of the
with respect to
is denoted by
is the
. If distinct vertices of
have distinct representations with respect to
, then
is called a resolving set or locating set for
[1]. A resolving set of minimum cardinality is called a metric basis for
and its cardinality is the metric dimension of
, denoted by
. The concepts of resolving set and metric basis have previously appeared in the literature (see [1-14]).
For a given ordered set of vertices of a graph
, the ith component of
is 0 f and only if
. Thus, to show that
is a resolving set it sufficient to verify that
for each pair of distinct vertices
.
Motivated by the problem of uniquely determining the location of an intruder in a network, the concept of metric dimension was introduced by Slater in [2] and studied independently by Harary et al. [3]. Applications of this invariant to the navigation of robots in networks are discussed in [4] and applications to chemistry in [1] while applications to problems of pattern recognition and image processing, some of which involve the use of hierarchical data structures are given in [5].
By denoting the join of
and
, a
is
for
and
(also known as
) is obtained from the
by alternately deleting
spokes. Caceres et al. [6] found the metric dimension of fan
and Tomescu et al. [7] found the metric dimension of
. Also Tomescu et al. [8] the partition and connected dimension of wheels.
Chartrand et al. proved:
Theorem 1: [1] A graph has metric dimension
if and only if
is a path.
Hence paths on vertices constitute a family of graphs with constant metric dimension. Similarly, cycles with
vertices also constitute such a family of graphs as their metric dimension is 2. Since
are the trivalent plane graphs obtained by the cartesian product of the path
with a cycle
, hence they constitute a family of
-
with constant metric dimension. Also Javaid et al. proved in [9] that the plane graph
constitutes a family of regular graphs with constant metric dimension as
for every
.
Let be a family of graphs of order
obtained from a prism
as shown in Figure 1 and Figure 2 respectively, by deleting the spokes
for
. We prove the following.
Theorem 2: Let with
, then
for
.
Let be a cycle with vertex set
and
be a path with vertex set
. Dragon graph
as shown in Figure 3, is a graph of order
obtained by identifying
of
with
of
. We prove the following.
Theorem 3: For all
.
2. Proofs
Proof of the Theorem 2: By Theorem 1,. We only need to show that
is a resolving set for
, which is obviously of minimal cardinality.
Figure 1. Prism Dn.
Figure 2. Graph 2Ck + {xk yk}.
Figure 3. Dragon graph.
Case (a) When for
Representations of all vertices from
are as follows,
It is easy to check that all the above representations are distinct. For example, suppose that for some fixed
and
. Then
and
, a contradiction.
Case (b) When for
Representations of vertices from
are as follows,
All the above representations are also distinct.
Proof of the Theorem 3: By Theorem 1, . We only need to show that there is a resolving set
of cardinality 2.
Case (a) When for
The set
is a resolving set for the graph
. Representations of all vertices from
are as follows,
and
,
It is easy to check that all the representations are distinct. For example, suppose that for some fixed s and j. Then
because
, a contradiction.
Case (b) When for
The set
is a resolving set for the graph
. Representations of all vertices from
are as follows,
and
,
All the above representations are distinct.
3. Acknowledgements
This research is partially supported by FAST-National University of Computer and Emerging Sciences, Peshawar, Bahauddin Zakariya University, Multan and Higher Education Commission of Pakistan.
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NOTES
*Corresponding author.