Advances in Pure Mathematics
Vol.2 No.6(2012), Article ID:24365,2 pages DOI:10.4236/apm.2012.26055
Necessary Conditions for a Fixed Point of Maps in Non-Metric Spaces
Department of Mathematics and Physics, Colorado State University, Pueblo, USA
Email: ivan.raykov@colostate-pueblo.edu
Received July 17, 2012; revised September 3, 2012; accepted September 11, 2012
Keywords: Topological Space; Complete Metric Compact Space; Cauchy Sequence; Lipschitz Continuous Map; Contraction Map
ABSTRACT
The main purpose of the present work is to introduce necessary conditions for a map on a non-metric space, defined by using a map on a metric space, to have a fixed point.
1. Introduction
Let X denote a complete (or compact) metric space and also a continuous map of X onto Y, where Y is a bounded closed topological normal space with a countable base.
What must be the conditions, in the means of the meric space X, such that the continuous map from Y onto Y will have a fixed point?
We suppose that (see [1-3]):
the continuous map (not one to one) and the continuous map
are given and the continuous inverse map of f,
exists.
We remind that Banach contraction principle for multivalued maps is valid and also the next Theorem, proved by H. Covitz and S. B. Nadler Jr. (see [4]).
Theorem 1. Let be a complete metric space and
a conraction map (
denotes the family of all nonempty closed bounded (compact) subsets of X). Then there exists
such that
.
2. Main Result
We consider now the next theorem:
Theorem 2. Let denote a complete (or compact) metric space
and also:
a continuous map of
onto
, where
is a bounded closed topological normal space with a countable base.
We suppose also that the maps:
is continuous and onto.
and
exists and it is continuous.
If is a point from
and if we suppose also that
.
Then if the rest terms of the sequence are received from
and the rest of the terms of the sequence
are determined by
and if also
is a Cauchy sequence and therefore convergent to a fixed point
in
, then the sequence
will be also convergent to a fixed point
in
.
Proof. Let is a point from
and let us suppose also that
and let the rest terms of the sequence
are received from
.
Let also the rest of the terms of the sequence are determined by
.
If is a Cauchy sequence then for any
there exists an integer
, such that for all integers i and k,
and
will be satisfied the inequality
and therefore the Cauchy sequence will be convergent with a fixed point
in X, and because X is complete (or compact), i.e.
Since and
and
is a continuous map and
is continuous map onto the closed and bounded space
, and also
and
, therefore the sequence
will be also convergent with a fixed point
in
, such that
and
, i.e.
Q.E.D.
3. Acknowledgements
We express our gratitude to Professor Alexander Arhangelskii from OU-Athens for creating the problem and to Professor Jonathan Poritz and Professor Frank Zizza from CSU-Pueblo for the precious help for solving this problem, and to Professor Darren Funk-Neubauer and Professor Bruce Lundberg for correcting some grammatical and spelling errors.
REFERENCES
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- J. Dugundji, “Topology,” Allyn and Bacon, Inc., Boston, 1966.
- S. W. Davis, “Topology,” McGraw-Hill, Boston, 2005.
- L. Gorniewicz, “Topological Fixed Point Theory of Multivalued Mappings,” Springer Verlag, Berlin, 2006.