Advances in Pure Mathematics
Vol.2 No.6(2012), Article ID:25018,5 pages DOI:10.4236/apm.2012.26070
Some Properties on the Error-Sum Function of Alternating Sylvester Series
Science College of Hunan Agricultural University, Changsha, China
Email: Huiping_J@126.com, *lum_s@126.com
Received July 11, 2012; revised September 21, 2012; accepted September 29, 2012
Keywords: Alternating Sylvester Series; Error-Sum Function; Hausdorff Dimension
ABSTRACT
The error-sum function of alternating Sylvester series is introduced. Some elementary properties of this function are studied. Also, the hausdorff dimension of the graph of such function is determined.
1. Introduction
For any
, let
and
be defined as
(1)
where
denote the integer part. And we define the sequence
as follows:
(2)
where
denotes the nth iterate of
.
It is well known that from the algorithm (1), all
can be developped uniquely into an infinite or finite series
(3)
In the literature [2], (3) is called the Alternating Balkema-Oppenheim expansion of x and denoted by
for short. From the algorithm, one can see that T maps irrational element into irrational element, and the series is infinite. While for rational numbers, in fact, we have
is rational if and only if its sequence of digits
is terminate or periodic, see [1-3].
For any
and
, define

From the algorithm of (1), it is clear that
(4)
For any
, let
be its Alternating Sylvester expansion, then we have
for any
. On the other hand, any
of integer sequence satisfying
for all
is a Sylvester admissible sequence, that is, there exists a unique
such that
for all
, see [9].
The behaviors of the sequence
are of interest and the metric and ergodic properties of the sequence
and
have been investigated by a number of authors, see [1-3].
For any
, define
(5)
and we call
the error-sum function of Alternating Sylvester series. By (4), since
for all
, then
and
is well defined. In this paper, we shall discuss some basic nature of
, also the Hausdorff dimension of the graph of
is determined.
2. Some Basic Properties of 
In what follows, we shall often make use of the symbolic space.
For any
, let

Define

For any
, write
(6)
(7)
We use
to denote the following subset of (0,1],
(8)
From theorem 4.14 of [8], we have
when
is even, and
when
is odd. Finally, define
(9)
Lemma 1. For any
and
1)
(10)
2)
(11)
3)
(12)
Proof. 1) Since
and
, so when
, we can get

accordingly

we write
, so
.
Now
implies
for 
Thus

let
, we have
and
, thus

2) From 1) we know that

from the definition of
we also know that
, so 

thus

3) Since as
,

Thus

Let

Proposition 2. For any
, if
, then
is left continuous but not right continuous. If
, then
is right continuous but not left continuous.
Proof. For any
and
, write
,
, where
,
are given by (6) and (7).
Case I,
, then
(13)
(14)
and
. For any
, since when 

This situation is included in Case II, so we can take
and

i.e.


By (2),

which implies

and

Let
, we get
and
, thus

and this implies
is left continuous at
.
Let


then

Let
, we have

and this implies
is not right continuous at
. For
(15)
following the same line as above, we have

Case II 
Let
(16)
(17)
Following the same line as above, we have


and
is right continuous.
Corollary 3. For any
and
, write
,
. Then for any
, if
then

where
.
From the corollary, for any 

where
is the Lebesgue measure of
.
Theorem 4.
is continuous on
.
Proof: For any
and
, let
be its Alternating Sylvester expansion. For any
, write
. By (Corollary 3), for any
, we have

Write
, where

Theorem 5. If
, then there exists
, such that 
Proof. Set
, then
has the same continuity as
. Write

trivially,
, then the set is well defined.
If
, then by the left continuity of
, we have

As a result, there exists a
such that for any
.
If
, since
is not left continuous, then
such that for any
,
, that is
.
Following the same line as above, we can prove
.
Now we shall prove that
. We can choose
such that
, if
, then

if
, then

In both case
. Following the same line as above, we can prove
, and
.
Therefore, there exists
, such that 
Theorem 6.
and 
Proof.

Let
, then
thus

thus,

Through the MATLAB program we can get the definite integration

3. Hausdorff Dimension of Graph for 
Write

Theorem 7.
.
Proof. For any
,
is a covering of
. From (Cor 3),
can be covered by
squares with side of length
. For any
,

Thus, 
Since
then

so
.

Figure 1. The graph of S(x).
4. Acknowledgements
This work is supported by the Hunan Education Department Fund (11C671).
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NOTES
*Corresponding author.

