Advances in Pure Mathematics, 2011, 1, 284-285
doi:10.4236/apm.2011.15051 Published Online September 2011 (http://www.SciRP.org/journal/apm)
Copyright © 2011 SciRes. APM
Property S[a,b]: A Direct Approach
George Nickolaos Miliaras
American University of Athens, Athens, Greece
E-mail: gmiliara@yahoo.gr, gmiliaras@aua.edu
Received May 18, 201 1; revised June 17, 2011; accepted June 30, 2011
Abstract
In this paper we prove directly that the property
,Sab, implies
,ab -compact, and under certain condi-
tions it implies -compact.
,ab
Keywords: Compactness number, -compact,
,ab
,ab -compact, property
,Sab
1. Introduction
Compactness is one of the oldest and the most famous
notions in mathematical analysis and especially in to-
pology. A partial generalization is
,ab -compactness
[1-8]. This has been shaped to property
,Sab by
Vaughan in 1975 [8], (page 253 and 256-257) who
proved that
,ab -compactness is equivalent to
,Sab if (Theorem 2C) using the Corol-
lary of Lemma 2 (pages 254-255).

b acf
In this paper we are going to prove directly some-
thing stronger, which we will need the following defi-
nitions:
Definition 1. The compactness number
Cn X of
a space
X
is the least cardinal such that every
open cover of k
X
has a subcover of cardinality less
than .
k
Definition 2. A space
X
is called
,ab
U
-compact
(
-compact) if every open cover of
,ab
X
with
Ub (Ub) has a subcover of cardinality strictly
less than .
a
Definition 3. A space
X
is said to have property
,Sab if every open cover of
X
of regular cardi-
nality less than b, has a subcover of cardinality strictly
less than a.
2. Main Result
Theorem. Let
X
have the property
,Sab, then
X
is -compact, and if is regular or if
, then
,ab
a
b

bcf
X
is -compact, furthermore
either , or, .
],[ ba
ab

Cn Xb

CXn
Proof. We study the following three cases:
Case 1.

Cn Xb
Let * be an open cover of U
X
with *
Uk
be
the first singular cardinal greater than , with the
property that h as no subcover with cardinality less
than .
a
*
U
a
If , then clearly
kb
X
is
,ab -compact.
If kb
, then clearly
X
is
-compact.
,ab
Assume that kb
. Since , there
exists an open cover of

CnXkb
*
V
X
which *
Vk
.
Then at least one *
UU
is covered by a collection
**
VV
with *
V
k
, such that no subcollection
of *
V
with less than
elements can cover U. If
such a U didn't exist it would contradict the hy-
pothesis
XCn bk. Consider the collection of
open sets
V
*
U *
WV

. Let a collection V
*
WW k

of k
elements of *
W and let W
be the union of the rest of the remaining elements of
* (if there are any left). We have W
*
UW W
,
put
**
UU U
, then * is an
open cover of

W
**
SUW


X
with
kS* since *
Uk
,
*
Wk
and
1W, then * has a subcover
with cardinality less than , since is a regu-
lar cardinal and
S
ak b
X
has property
,bSa . Now, since
* refines *, must have a subcover with car-
dinality less than , thus
SU U*
a
X
is
-compact.
,ab
Now, if is a regular cardinal then clearly
b
X
is
,ab -compact, since it is
-compact, and has
property
,ab
,Sab.
Assume that is singular and . Let
b

cf ba
*
UU b
, be an open cover of
X
, with
*
Ub
, let
cfk ab
, choose cardinals b
,
k
with
bb
sup
. For every k
, let
bVU

, and let
 

k
*
VV. Then *
has a subcover *
V with V
*
Va
, since is
regular, and k
ka
X
has property
,Sab . Let
G. N. MILIARAS285

*
VV


, then 1, but VX

11
VUb

. Put

 

*1
UU b


, then
*1
Ub
b
, then since
X
is -compact, if
,ab
*
Ua
, it has a subcover *
U
with *
Ua
, thus
X
is
,ab -compact.
Case 2.

Cn Xb
bAssume that is a limit cardinal. Since
X
has
property
,Sab, for every b
,
X
has property
,Sa
, and therefore
X
is
a
,
-compact for
every b
, and if
is regular or ,

cf
a
X
is
,a
-compact, by case 1. Let *
U be an open
cover of
X
, since

Cn Xb
, * has a subcover
* such that U
U*
Ukb
b
. Now, since is a limit
cardinal, , it follows from the above that
b
k
X
is
-compact, so *
U has a subcover *
U,ak


such
that *
Ua
 , thus
X
is
,ab -compact and since
, we must have . Assume
that is a successor cardinal , then

Cn X
b
b

CnX
ab
k
X
has
property

, therefore
,k
Sa
X
has property
,Sak and therefore
X
is
-compact. If is
regular or ,
,ak k

k acf
X
is
,ak -compact, by case
1, and since Cn ,

Xk
X
is -compact,
thus ,ak

X
is
,ab -compact, and since

Cn Xb
we
have .

CnX
cf
ab
Assume that . Let * be an open cover
of

k aU
X
with *
Uk, with no subcover with cardinal-
ity less than . Let * be an open cover of k V
X
with
*
Vk
. Consider the open cover

***
. Then ,UVV WW VUU*
Wk
and
also refines *, since
*
W U
X
has property
, has a subcover *
W with ,Sa
k

 *
W*
Wa
and since *
W refines *, has a subcover *
U
U*
U
with *
Ua
, thus
X
is
,ak -compact and since
,

Cn Xkb
X
is
,ab -compact and using the
previous argument
XabCn.
Case 3.
Cn Xb
Let
X b
Cn
, then
X
has property
,Sa
,
so
Xb a
Cn
 by case 2. Now since
aCn X
,
X
is
,ac -compact for every ,
therefore ca
X
is
,ab -compact.
The proof is complete.
3. References
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Espaces Topologiques Compacts,” Koninklijke Akademie
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[3] G. Miliaras, “Cardinal Invariants and Covering Properties
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doi:10.1016/0166-8641(95)90001-2
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Copyright © 2011 SciRes. APM