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Open Journal of Discrete Mathematics, 2012, 2, 145-148 http://dx.doi.org/10.4236/ojdm.2012.24029 Published Online October 2012 (http://www.SciRP.org/journal/ojdm) Mean Cordial Labeling of Graphs Raja Ponraj1, Muthirulan Sivakumar2, Murugesan Sundaram1* 1Department of Mathematics, Sri Paramakalyani College, Alwarkurchi, India 2Department of Mathematics, Unnamalai Institute of Technology, Kovilpatti, India Email: ponrajmaths@indiatimes.com, sivamaths.vani_r@yahoo.com, sundaram_spkc@rediffmail.com Received August 12, 2012; revised September 4, 2012; accepted September 17, 2012 ABSTRACT Let f be a map from V(G) to. For each edge uv assign the label 0,1, 2 2 f ufv . f is called a mean cordial la- beling if 1 ff viv j and 1 ff eie j, ,0,1,2ij, where f vx and denote the number of vertices and edges respectively labelled with x ( f ex 0,x1,2 ). A graph with a mean cordial labeling is called a mean cor- dial graph. We investigate mean cordial labeling behavior of Paths, Cycles, Stars, Complete graphs, Combs and some more standard graphs. Keywords: Path; Star; Complete Graph; Comb 1. Introduction The graphs considered here are finite, undirected and simple. The vertex set and edge set of a graph G are de- noted by V(G) and E(G) respectively. The cardinality of V(G) and E(G) are respectively called order and size of G Labelled graphs are used in radar, circuit design, com- munication network, astronomy, cryptography etc. [1]. The concept of cordial labeling was introduced by Cahit in the year 1987 in [2]. Let f: V(G) to{0,1} be a function. For each edge uv assign the label f ufv. f is called a cordial labeling if 1 ff viv j and 1, ff eie j where and denote the number of vertices and edges respec- tively labelled with x (x = 0, 1). A graph with admits a cordial labeling is called a cordial graph. Product cordial labeling was introduced by M. Sundaram, R. Ponraj and Somasundaram [3]. Here we introduce a new notion called mean cordial labeling. We investigate the mean cordial labeling behavior of some standard graphs. The symbol ,0,1ij f vx f ex x stands for smallest integer greater than or equal to x. Terms not defined here are used in the sense of Harary [4]. 2. Mean Cordial Labeling Definition 2.1. Let f be a function from V(G) to {0,1,2}. For each edge uv of G, assign the label 2 f ufv . f is called a mean cordial labeling of G if 1 ff viv j and 1, ff eie j ,0,1,2ij where f vx and f ex denote the num- ber of vertices and edges labelled with x () re- spectively. A graph with a mean cordial labeling is called mean cordial graph. 0,1, 2x Remarks 2.2: If we restrict the range set of f to {0,1},the definition 2.1 coincides with that of product cordial labeling. Remarks 2.3: If we try to extend the range set of f to 0,1, ,2kk, the definition 2.1 shall not workout since 0 f v becomes very small. Theorem 2.4: Every graph is a sub graph of a con- nected mean cordial graph. Proof: Let G be a given (p,q) graph. Take three copies of Kp. Let 123 respectively denote the first, se- cond and third copies of Kp. Let ,,GGG 12 ,,vVG uVG wVG 3 . Let G* be the graph with 12 VGVG VGVG 3 and 123 ,EGEG EGEGuvvw . Clearly G* is a super graph of G. Assign the label 0 to all the vertices of G1,1 to all the vertices of G2, 2 to all the vertices of G3. Then and 012 fff vvv p p 02 f p e , 11 2 f e, 21 2 f e p . Therefore this labeling is a mean cordial labeling of G*. Theorem 2.5: Any Path is a mean cordial. n P *Associate professor (retired). C opyright © 2012 SciRes. OJDM R. PONRAJ ET AL. 146 Proof: Let be the Path . n P n12 n uu u Case (1): 0 mod 3 3.t Let Define n2,1 i f uit , 1, 1 ti f ui t 0, 1 , 2ti f uit . Then and 01 ff vv 2 f vt 01,1 2 fff etee .t 1t 1 Hence f is a mean cor- dial labeling. Case (2): 1 mod 3n 31. Let Assign labels to the vertices i as in case (1). Then assign the label 0 to the vertex . Here. and f Hence f is a mean cordial labeling. nt 1uin n u 0,et 012 fff vvv 2.t 1 ff ee Case (3): 2 mod 3n 32. Let Assign labels to the vertices i as in case (2). Then assign the label 1 to the vertex n u. Here nt 1uin 011,2 ff f vvtv ,t f and e11.t 02 ff eet. Hence f is a mean cordial labeling. Illustration 2.6: Mean cordial labeling of is shown in Figure 1. 6 P Theorem 2.7: The Star 1,n K is a mean cordial iff . 2n Proof: Let and 1, ,:1 ni VKuui n :1 .ui n 1,ni EK u For , the result follows from Theorem 2.5. As- sume If possible let there be a mean cordial la- beling f. 2n 2.n Case (1): 0.fu fu fv Then for all edge uv. This forces a contradiction. 2 0. 2.fu 2 f e Case (2): In this case again a contradiction. 0e0 f, , Case (3): 1.fu 0e Here also a contradiction. 0 f Hence 1,n K is not a mean cordial for all 2.n Theorem 2.8: The cycle is mean cordial iff . n C uu 1,2 mod 3nC Proof: Let be the cycle n 0n12 1n uu Case (1): mod 3 t Let . Then . In this case a contradiction 3n 0 f e n 012 fff vvv od 3 t 1,t 1 mCase (2): Let Define 31.nt 0,1 1 i f uit 1,1 1ti f ui t 2, 1 , 21ti f uit t Then 01 f vt, 12 ff vv and 2 1 2 2 2 1 1 0 0 0 1 01,t f v 12 ff vv t and Figure 1. Mean cordial labeling of P6. Then 11et f , 02. ff eet Hence f is a m Case (3): ean cor- dial labeling. mod 3 2 2n Let 3nt . Define 0,1 1 i f uit, 1, 1 1ti f uit , 2,11 21ti f uit Then 1 f vt, 02 ff vvt1 and 11et f , 02.eet ff Hence f is a mean cor- he Complete graph dial labeling. Theorem 2.9: Tn K is mean cor- dial iff 2.n Proof: Clearly 1 K and 2 K are mean cordial by Theorem 2.5. Assu2.n possible let there be a mean cordial labeling f. Case (1): me If 3 , 1.t 0 modn Let 3nt Then 012 fff vvvt t 02 f e , t 22 12 f et t , and 2 22 f t et . Then a con- tradiction. Case (2): 2 102 ff ee t1, 1 mod 3n 1 Let 3nt Subcase (i ) : 01 f vt 12 ff vvt 1t 02 f e , 11 2 f et tt t 1t and 2 22 f t et , 2 12 2 ff ee tt1, a contra- diction. Subcase ( i i ) : 11 f vt 1t 02 ff vvt t 02 f t e , 2 11 2 f et t and 21 2 f t et t . 2 20 ff eett1, a con- tradiction. Subcase (iii): 21 f vt t t 01 ff vv 0, 2 f t e 2 11 2 f et tt and 1 21 2 f t et .t Then 102 ff ee tt 21, a contradiction. Case (3): 2 mod 3n Let 32nt Subcase ( i) : 0 f vt 12 ff vv t 1 1 1t 02 f t e , 11 2 f et tt t and 2 1 21 2 f t et . Then Copyright © 2012 SciRes. OJDM R. PONRAJ ET AL. 147 2 1023 ff ee tt 1vt 1, a contradiction Subcase ( i i ) : f 02 ff vvt t 1 1 t t 1, 1 1tt 1, 1 02 f t e , and 2 11 2 f et t 1 21 2 f t et . Then 2 20 ff eett 2vt a contradiction. Subcase (iii): ft 01 ff vvt 1 1 02 f t e 2 f t et and 2 11 2 f et 21 t 2 Then a contradic- tio 2 10 1 ff eet tt n. Theorem 2.10: The Wheel is not a mean cordial gr n W aph for all n Proof: Let W where n C is the cycle 12 1n uu uu and 1 VK If possible let there be a me labeling f. 3. 1nn CK . u an cordial e (1): Cas 0 mod 3n Let Theze of the wheel is 3nt Subcase ( i) : n the si6.t 0,fu t Here , a contradiction. 0 1 f et Subcase ( i i ) : . 12t 1or 2fu In this case gain a contradiction. 0,et a f 1 mod 3nC ase (2): Let 31nff etet ac- cording as .nt The 021or 0 0,fu or 0,fu this is a contra- diction. Case (3): 2 mod 3n Similarly to case (1e get a contradiction. ), w Theorem 2.11: 1, n SK is mean cordial, where S(G) debdivision of G. (i): notes su Proof: Let and 1, ,, :1 nii VSKuuvin ,:1 iii ESKuuuvin 1,n Case 0 mod 3n 3.t Let n Define 0,fu 0,1, i f uit 1,1 2 ti f ui t 0,1, i , f vit 2,12 , ti f vi t, Then 021 f vt 122 ff v vt and 01 ff ee 2,t 22 f et. o Let 1 He ean crdial lbeling. nce f is a m e (2): a Cas 1 mod 3 1 Assign labels to the vertices ,i uu and 11 i vin as in case (1). Then assign the label 1 and 2 to the vertices and v respectively. Here n 3tn n un and , 0122 fff vvv t 02 f et 122 ff ee t1, Hence f is a mean cordial label- ing. Case (3): 2 mon 32.ntd 3 Let vin Assign labels to the vertices and i (1 ,i uu 1 ) as in case (2). Then assign the label 0 and 2 to the vertices, respectively. Here n un v 022 ff vv t2, and 12v1 ft 122 f et , 2 ff eet 02 1, Hence f is a mean cordial labeling. Illustration 2.12: Mean cordial labeling of 1,6 SK is shown in Figure 2. Theorem 2.13: The comb is mean cordial where 1n PK 12 GG denotes the corona of and . 1 Proof: Let be the Path . Let G uu u 2 G n P12 n 1nn VP KVP:1 i vi n , :1 ii uvi n 1nn EP KEP Case (1): 0 mon 3.nt d 3 Let 2, 1 i f uit , 1, 1 ti f ui t 20, 1 ti f ui t , 2,1 i f vit 1, 1 ti f vi t , 20,1 ti f vi t Then 2 f v01 ff vv 2t and 122, ff ee t02 f e t1, Hence f is a mean cordial labeling. Case (2): d 31 mon 31nt Let i v1in . Assign labels to the vertices and ( 1 i u n u ) as in case (1). Then assign the label 0 and 1 to the vertices and . Here n v 1,22 f v012 ff vv t,t and 022, ff ee t and 121 f et Hence f is a mean cordial labeling. Case (3): d 32 mon 32.nt Let i (1in Assign labels to the vertices i u & v2 ) as in case (1). Then assign the label 0, 2 and 0, 1 to the vertices u and respec- tively. Here 1, n u nn1, n vv 02 f vt2, and 122t1 ff vv 01 fff eee221.t Hence f is a mean cor- dial labeling. Theorem 2.14: PnΘ2K1 is mean cordial. 0 1 1 1 1 1 11 1 0 0 0 0 0 0 0 2 2 2 2 2 2 2 2 0 Figure 2. Mean cordial labeling of S(K1,6). Copyright © 2012 SciRes. OJDM R. PONRAJ ET AL. Copyright © 2012 SciRes. OJDM 148 Let 2, ,, :1 ni VKuvui n and Proof: Let Pn be the Path 12 Let vi and wi be the pendant vertices which are adjacent to . n uu u ,1 . i uin 2, ,:1 nii EKuuvuin . 2,1 K and 2,2 K are mean cordial by Theorem 2.5 and 2.8 respectively. Assume . Suppose f is a mean cordial labeling of 2,n 2n K . Clearly either 0fu or Without loss generality we can assume so that fv 0 0. fu 0.fv Case (1): n is even. Define 0, 12 in fu i 2 1, 12 ni n fu i 0 mod 3nCase (1): 0, 12 in fv i 3.tn Then 0or f ett Let 1, a contradiction since the size of 2,n K is 6.t 1, 12 in fw i od 31 mnCase (2): ce Let n = 3t + 1. Here again a contradic- tion. 0 ft, 2 2, 12 ni n fv i Case (3): 2 mod 3n 0or f ett 2,n Let n = 3t + 2. Here 1, again a con- tradiction to the size of K . 2 2, 12 ni n fw i 3. Conclusion Then and 012 fff vvv 01,12.eneen n fff In this paper we introduced the concept of mean cordial labeling and studied the mean cordial labeling behavior of few standard graph. The authors are of the opinion that the study of mean cordial labeling behavior of graph ob- tained from standard graphs using the graph operation shall be quite interesting and also will lead to newer re- sults. Hence f is a mean cordial labeling. Case (2): n is odd. Define 1 0, 12 in fu i 1 2 1 1, 12 ni n fu i 4. Acknowledgements 3 0, 12 in fvi The authors are thankful to the referee for their valuable comments and suggestions. 3 1, 12 in fwi REFERENCES 11 22 0 nn fv fw [1] J. A. Gallian, “A Dynamic Survey of Graph Labeling,” Electronic Journal of Combinatorics, Vol. 18, 2011, pp. 1-219. 11 22 1, 2 nn fv fw [2] I. Cahit, “Cordial Graphs: A Weaker Version of Graceful and Harmonious Graphs,” Ars Combinatoria, Vol. 23, No. 3, 1987, pp. 201-207. 11 22 1 2, 12 nn ii n fv fwi [3] M. Sundaram, R. Ponraj and S. Somosundram, “Product Cordial Labeling of Graph,” Bulletin of Pure and Applied Sciences, Vol. 23, No. 1, 2004, pp. 155-162. Then and 012 fff vvv 01,12.eneen n fff [4] F. Harary, “Graph Theory,” Addision Wisely, New Delhi, 1969. Hence f is a mean cordial labeling. Theorem 2.15: The 2,n K is a mean cordial iff 2.n Proof: |