Advances in Pure Mathematics, 2012, 2, 104-108
http://dx.doi.org/10.4236/apm.2012.22014 Published Online March 2012 (http://www.SciRP.org/journal/apm)
On P-Regularity of Acts
Akbar Golchin, Hossein Mohammadzadeh, Parisa Rezaei
Department of Mathematics, University of Sistan and Baluchestan, Zahedan, Iran
Email: agdm@math.usb.ac.ir
Received September 27, 2011; revised December 17, 2011; accepted December 30, 2011
ABSTRACT
By a regular act we mean an act that all its cyclic subacts are projective. In this paper we introduce P-regularity of acts
over monoids and will give a characterization of monoids by this property of their right (Rees factor) acts.
Keywords: P-Regularity; Rees Factor Act
1. Introduction
Throughout this paper will denote a monoid. We refer
the reader to ([1]) and ([2]) for basic results, definitions
and terminology relating to semigroups and acts over
monoids and to [3,4] for definitions and results on flat-
ness which are used here.
S
S
,
A monoid is called left (right) collapsible if for
every
s
s
zs zsS there exists such that zS

s
zsz
S
,,
. A submonoid of a monoid is called
weakly left collapsible if for all
P
s
sP
zS
the
equality

s
zsz
implies that there exists an element
such that .
uPus
,
us
SA monoid is called right (left) reversible if for
every
s
s
S, there exist such that
,uvSus vs

.
s
us
klK
 
,\ ,.Sx ySKxtytKxtyt 
v
A right ideal K of a monoid S is called left
stabilizing if for every , there exists such
that and it is called left annihilating if,
K
lk k
t
If for all ,\
s
tSK

:S
S
and all homomorphisms
Ss StS
  
,
f
sft Kfsft
then is called strongly left annihilating. K
A right S-act
A
satisfies Condition if
for

P
as a s

,,A,aa
,
s
s
S
S implies the existence
of such that and
,,uvaA
 ,aau

a av
 
,aa A
.usvs
A right S-act A is called connected if for
there exist 11
,,, ,
nn
s
tstS11
,,
n
aaA
and
111
12 22
1nn n
asa t
as at
as at
SF
PF WPF
WKF PWKF
TKF
such
that
We use the follow ing abbreviations:
Strong flatness = ;
Pullback flatness = ;
Weak pullback flatness = ;
Weak kernelflatness = ;
Principal weak kernelflatness =;
Translation kernelflatness = ;
WP ; Weak homoflatness =
Principal weak homoflatness = PWP
WF PWF
TF
S
;
Weak flatness = ;
Principal weak flatness =;
Torsion freeness = .
2. Characterization by P-Regularity of Right
Acts
Definition 2.1. Let be a monoid. A right S-act
A
is
called P-regular if all cyclic subacts of A satisfy Condi-
tion
P.
We know that a right S-act
A
is regular if every cy-
clic subact of
A
is projective. It is obvious that every
regular right act is P-regular, but the converse is no t true,
for example if is a non trivial group, then is right
reversible, and so by ([2, III, 13.7]), S is P-regular,
but by ([2, III, 19.4]),
S S
S
is not regular, since has
no left zero element. S
S
S
Theorem 2.1. Let be a monoid. Then:
1)
is P-regular if and only if is right reversi-
ble. S
SS
2) S is P-regular if and only if all principal right
ideals of satisfy Condition
P.
A
is a right S-act and i
A
iI, are subacts of 3) If ,
A
, then iI i
A
is P-regular if and only if i
A
is
P-regular for every iI
.
4) Every subact of a P-regular right S-act is P-regular.
Proof. It is straightforward. q.e.d.
Here we give a criterion for a right S-act to be P-
C
opyright © 2012 SciRes. APM
A. GOLCHIN ET AL. 105
regular.
Theorem 2.2. Let be a monoid and S
A
a right S-
act. Then
A
is P-regular if and only if for every aA
and ,,
x
yS ax ay,uv S implies that there exist
such that and .
aauav ux vy
Proof. Suppose that
A
is a P-regular right S-act and
let , for and
ax ay aA,
x
ySaS. Then satis-
fies Condition . But

PkerSa
aS
, and so by ([2,
III, 13.4]), we are done.
Conversely, we have to show that satisfies Con-
dition aS
P for every a. Since AkeraS Sa
, then
it suffices to show that ker a
S
satisfies condition (P)
and this is true by ([2, III, 13.4]) . q.e.d.
We now give a characterization of monoids for which
all right S-acts are P-regular.
Theorem 2.3. For any monoid the following state-
ments are equivalent: S
 

P

P

P
x0S
S

0,
1) All right S-acts are P-regular.
2) All finitely generated right S-acts are P-regular.
3) All cyclic right S-acts are P-regular.
4) All monocyclic right S-acts are P-regular.
5) All right Rees factor S-acts are P-regular.
6) S is a group or a group with a zero adjoined.
Proof. Implications (1) (2) (3) (4) and
(3) (5) are obvious.
(4) (6). By assumption all monocyclic right S-
acts satisfy Condition , and so by ([2, IV, 9.9]), S is
a group or a group with a zero adjoin ed.
(5) (6). By assumption all right Rees factor S-acts
satisfy Condition and again by ([2, IV, 9.9]), S is a
group or a group with a zero adjoined.
(6) (1). By ([2, IV, 9.9]), all cyclic right S-acts
satisfy condition , and so by definition all right S-
acts are P-regular as required. q.e.d.
Notice that freeness of acts does not imply P-regu-
larity, for if , with , then is free,
but S is not P-regular, otherwise
0, 1,S2
x
S
x
SxS satis-
fies Condition as a cyclic subact of S, and so

P
..0
x
xx, implies the existence of such that ,uv S
x
xu xv and , and this is a contradiction. 0ux v
Theorem 2.4. For any monoid the following state-
ments are equivalent: S
1) All right S-acts satisfying Condition
E

E
are P-
regular.
2) All finitely generated right S-acts satisfying Condi-
tion are
P-regular.
3) All cyclic right S-acts satisfying Condition
E
are P-regular.
4) All SF right S-acts are P-regular.
5) All SF finitely generated right S-acts are P-regular.
6) All SF cyclic right S-acts are P-regular.
7) All projective right S-acts are P-regular.
8) All finitely generated projective right S-acts are P-
regular.
9) All projective cyclic right S-acts are P-regular.
10) All projective generators in Act-S are P-regular.
11) All finitely generated projective generators in Act-
S are P-regular.
12) All cyclic projective generators in Act-S are P-
regular.
13) All free right S-acts are P-regular.
14) All finitely generated free right S-acts are P-regu-
lar.
15) All free cyclic right S-acts are P-regular.
16) All principal right ideals of S satisfy Condition
P.
,,
s
tz S 17)
 
,.zsztu vSzzuzvusvt  
 
 
  
 
S

P
Proof. Implications (1) (2) (3) (6)
(9) (12) (15), (1) (4) (5) (6), (4)
(7) (8) (9), (7) (10) (11)
(12) and (10) (13) (14) (15) are obvious.
(15) (16). As a free cyclic right S-act S is
P-regular, and so by (2) of Theorem 2.1, all principal
right ideals of S satisfy Condition .
(17). By ([2, III, 13.10]), it is obvious. (16)
(17) (1). Suppose the right S-act
A
satisfies
Condition
Eax ayand let
, for and aA
,
x
yS
. Then there exist and such that
aA
uS
aau
and ux uy
. Thus by assumption there exist
s
tS uusut. and
s
such that ,
xty
,aaua usas Therefore
 ,aa
uautat

s
xty, and so
by Theorem 2.2,
A
is P-regular. q.e.d .
Notice that cofreeness does not imply P-regularity,
otherwise every act is P-regular, since by ([2, II, 4.3]),
every act can be embedded into a cofree act. But if
0,1,,Sx20,x
with
then as we saw before, is
not P-regular, and so we have a contradiction. S
S
S
 
 
Theorem 2.5. For any monoid the following state-
ments are equivalent:
1) All divisible right S-acts are P-regular.
2) All principally weakly injective right S-acts are P-
regular.
3) All fg-weakly injective right S-acts are P-regular.
4) All weakly injective right S-acts are P-regular.
5) All injective right S-acts are P-regular.
6) All injective cogenerators in Act-S are P-regular.
7) All cofree right S-acts are P-regular.
8) All right S-acts are P-regular.
9) S is a group or a group with a zero adjoined.
Proof. Implications (1) (2) (3) (4)
(5) (6) and (5) (7) are obvious.
(6) (8). Suppose that
A
is a right S-act, is
an injective cogenerator in Act-S and is an injective
envelope of A (C exists by [2, III, 1 .23]). By ([5, Theo-
rem 2]),
B
C
DBC
D
is an injective cogenerator in Act-S,
and so by assumption is P-regular. Since
A
C, we
have
A
is P-regular.
A
D, and so by Theorem 2.1,
Copyright © 2012 SciRes. APM
A. GOLCHIN ET AL.
106
(7) (8). Let
A
be a right S-act. Then by ([2, II,
4.3]), A can be embedded into a cofree right S-act. Since
A is a subact of a cofree right S-act, by assumption A is a
subact of a P-regular right S-act, and so by Theorem 2.1,
A
is P-regular.
(8) (9). By Theorem 2.3, it is obvious.
x20x
(8) (1). It is obvious. q .e.d.
Theorem 2.6. Let S be a monoid. Then every strongly
faithful right S-act is P-regular.
Proof. By Theorem 2.2, it is obvious. q.e.d.
Although strong faithfulness implies P-regularity, but
faithfulness does not imply P-regularity, since every mo-
noid as an act is faithful, with
0, 1,S
is
faithful, but as we saw before, is not P-regular. Now
see the following theorem. S
S
.
Theorem 2.7. For any monoid S the following state-
ments are equivalent:
1) All faithfull right S-acts are P-regular.
2) All finitely generated faithfull right S-acts are P-
regular.
3) All faithfull right S-acts generated by at most two
elements are P-regular.
4) S is a group or a group with a zero adjoined.
Proof. Implications (1) (2) (3) are obvious.
(3) (4). By Theorem 2.3, it suffices to show that
every cyclic right S-act is P-regular. Thus we consider a
cyclic right S-act and let SS
aS
A
aSSS Since S
is faithful, S
A
is faithful, also S
A
is generated by at
most two elements, thus by assumption S
A
is P-regular.
Since is a subact of
aS S
A
, by (4) of Theorem 2.1,
is P-regular as required. aS
(4) (1). By Theorem 2.3, it is obvious. q.e.d.
S
Since regularity does not imply flatness in general,
P-regularity also does not imply flatness in general, but
as the following theorem shows, for regular monoids P-
regularity implies flatness.
Theorem 2.8. Let S be a regular monoid. Then every
P-regular right S-act is flat.
Proof. Suppose that S is a regular monoid,
M
is a
left S-act and S
A
is a P-regular right S-act. Let
in S
am
a m

A
Mam
for S and
We show holds also in
S
,aa
a
A
m
,
SM
.
.
mm
A
Sm Sm
Since in ama m
S
A
M
,
we have a tossing
11
2211
3 32 2
''
kk
sm m
smt m
sm tm
m tm




11
,,,
kk
11
1
12 22
1
kk k
as a t
as at
as at
of length , where k,,
s
stt S
.
kS
M
1,k
,
1
1
,, ,
kS
aaA
1,,mm
If
then we have
11
11 11
.
s
mm
asa tmt m


S1
asa t
Since is regular, the equality 1
at atss implies
that 1 111

, for 1

1
.Vs
Since S
s
A
is P-re-
gular, there exist S
aA
and uv such that ,S
aa
uav
 
1111
.vt s s
and ut
From the last equality
we obtain 1 1111 111.umutm vtssm vtsm


11
msm Since
, we get 11 ,
s
smm
and so we have
111 11 1
11 1111
''
amassmassmat sm
autsm avtsm avtsm
aumaumam

 


 
 
A
Sm Sm
in S
2k.k
1
asa t
.
We now suppose that and that the required
equality holds for every tossing of length less than
From 11
we obtain equalities 11 1111
at atss
for
11
s
Vs
111
asas tt and 1
for 1. Since

1
tVt
S
A
is P-regular, there exist 12
,S
aaA

12
,,
12
,vv S and uu
such that 11111 ,aauav
 
ut vtss 111111
2 12 111
,.aauavus vstt and
222 2
 

21 12
22111112211 1
usmum
ausaut usmutm
 

122111
112223 32 2
1
kk kkk
usm utm
ausat sm tm
asatm tm
 



1.k
Thus we have the fol-
lowing tossing
of length 1 and
of length
From the tossing of length 1, we have
22 1122
aumausm

 S
in
A
M
1122
aumausm , and so we have
22



2122S
in
A
SumSusm
122111 11111 111,usmutm vtssmvtsmSm

.
Since

22 1122
aumausm
we have



S
in
A
Sm Sm
1k
1111
autmam
.
Also from the tossing of length , we have

 S
in
A
M
. Thus we have
1111
autmam

A
 in
11 1SSut mSm
11111 1,utmvtsm Sm
Since
1111
autmam
we have



,
S
in
A
Sm Sm
2222112 2
1111
amaumauma usm
autmam
and
so

 
 
 
S
A
Sm Sm
in as required. q.e.d.
Copyright © 2012 SciRes. APM
A. GOLCHIN ET AL. 107
3. Characterization by P-Regularity of Right
Rees Factor Acts
In this section we give a characterization of monoids by
P- regularity of right Rees factor acts.
Theorem 3.1. Let S be a monoid and S
K
a right
ideal of S. Then S is P-regular if and only if
S
SK
K
S and S is right reversible or 1K
S and all
principal right ideals of S satisfy Condition
.P
Proof. Let S
K
be a right ideal of S and suppose that
S
SK is P-regular. Then S satisfies Condition (P)
If S
SK
K
S, then by ([2, III, 13.7]), S is right reversible,
otherwise by ([2, III, 13.9]), 1K
S, and so S
SK S
.
Thus by (2) of Theorem 2.1, all principal right ideals of S
satisfy Condition
.P
Conversely, suppose that S
K
is a right ideal of
If S
.S
K
S and S is right reversible, then by (1) of Theo-
rem 2.1, SS
is P-regular. If SK 1
S
K and all
principal right ideals of satisfy Condition
S
P, then
by (2) of Theorem 2.1, S
SK S
is P-regular. q.e.d.
Although freeness of acts implies Condition
P
,x20x
in
general, but notice that freeness of Rees factor acts does
not imply P-regularity, for if with
0, 1,S
,
and S0,
K
S then 0S
SK S
S
S as a Rees fac-
tor act is free, but as we saw before, is not P-regu-
lar.
S S
SS
Now let see the following theorem.
Theorem 3.2. Let be a monoid and
U be a
property of S-acts implied by freeness. Then the follow-
ing statements are equivalent:
1) All right Rees factor S-acts satisfying property
U
-regular. are P
2) All right Rees factor S-acts satisfying property
U
fy Condition

P anither S contains no left zero
or all principal right ideals of S satisfy Condition
satis d e
P.
Proof.
-acts satisfyin
(1) (2). By definiti Rees factor
gon all right
S property

U satisfy Condition
.P
Suppose now that S containseft zero 0
z. Then

00S
a l
K
zS z is a right ideal of ,S and so
SS
S. by as-
p
SK Since
).
S
S is free, S
S P-regular,
and so alrincipal right ideals of S satisfy
Condition

P.
(2) (1Let
is
sumtion,l p
S
SK erty satisfies prop
U for
the rigideal S
ht
K
o Then by assumptionf S.S
K
satisfies Conditi

PNow there are two cas
follows:
Case 1
S
on . es as
. S
K
S. Then SS
SK so by ([2, III,
le, thus by
 , and
13.7]), S reversib(1) of Theorem 2.1, is right
SS
SK  is P-regular.
S
Case 2.
K
is a proper right ideal of S. Then by ([2,
III, 13.9]), 1
S. Thus

0,
S
K
K
z fo some 0
zSr
,
and so 0
z ption all prl
right ides of S satisfy Condition

P, that is
is left zero. Thus by assuincipa
al m
SS
SK S
is P-regula r . q.e. d.
y 3.1. For any monoiCorollar d S the following state-
mfactor S-acts satisfying Condition
ents are equivalent:
1) All right Rees
are P-regular.
) All WPF righ
P
2t Rees factor S-acts are P-regular.
PF
SF
roj lar.
P-e right Rees factor S-acts are P-regular. deals
of s
3) All right Rees factor S-acts are P-regular.
4) All right Rees factor S-acts are P-regular.
5) All pective right Rees factor S-acts are P-regu
6) All Rees factor projective generators in Act-S are
regular.
7) All fre
8) S contains no left zero or all principal right i
Satisfy Condition
.P
P oof. By Theorem 3.2s obr, it ivious. q.e.d. ing state-
mees factor S-acts are P-regular.
lat rl S
Corollary 3.2. For any monoid S the follow
ents are equivalent:
1) All WF right R
2) All fight Rees factor S-acts are P-regular.
3) S is not right reversible or no proper right idea
K
,
2
S of S is left stabilizing, and if S contain
, the all principal right ideals f S satisfy
Condition
Ks a
left zerono
.P
Proof. Itw follos from Theorem 3.2, ([2, IV, 9.2]), and
th
. For any monoid S the following state-
mRees factor S-acts are P-regular.
is righ
at for Rees factor acts weak flatness and flatness are
coinside. q.e.d.
Corollary 3.3
ents are equivalent:
1) All PWF right
2) S t reversible, no proper right ideal S
K
,
2Ks
left zero a
S of S is left stabilizing, and if S containa
, thenll princip al right ideals of Ssatisfy Con-
dition
.P
Proo fof. It llows from Theorem 3.2, and ([2, IV, 9.7]).
q. llary 3.4. For any monoid S the following state-
mes factor S-acts are P-regular.
er tive
mri
S
e.d.
Coro
ents are equivalent:
1) All TF right Re
2) EithS is a right reversible right cancella
onoid or a ght cancellative monoid with a zero ad-
joined, and if S contains a left zero, then all principal
right ideals of satisfy Condition
.P
Proof. It folls from Theorem 3.2, ad own([2, IV, 9.8]).
q. ollary 3.5. For any monoid S the following
st r S-acts satisfying Condition
e.d.
Cor
atements are equivalent:
1) All right Rees facto
P are P-regular.
S is not right r
W
2) eversible or no proper right ideal
S
K
, 2
S of S is left stabilizing and strongly left
ihnd if S contains a left zero, then all prin-
cipal right ideals of satisfy Condition
K
ann ilating, aS
.P
Proof. It follows m Theorem 3.2, and fro([3, Proposi-
Copyright © 2012 SciRes. APM
A. GOLCHIN ET AL.
Copyright © SciR APM
108
tio o monoid S the following state-
mfactor S-acts satisfying Condition
P
2) S ie and no propeght ideal S
2012 es.
n 3.26]). q.e.d.
Corollary 3.6. Fis
(2) (3) (4) are
ob
connected as a left S-act.
Proof. Implications (1)
r any
ents are equivalent:
1) All right Rees vious.
(1)
(5). By Theorem 3.3, and ([4, Corollary 24])
it vio
WP are P-regular.
s right reversiblis obus.
(2)
(6). B
K
r ri,
2
S of S is left stabilizing and left ann ihilating,d
ains a left zero, then all principal right ideals of S
satisfy Condition

P.
Proof. It follow
y Theorem 3.3, and ([6, Proposition 8])
it vio
K an
if S cont
s from Theorem 3.2 ([3, Corollary
3. nsider monoids over which P-regularity of
R

U be a prop-
er n a
, and
is obus.
(4)
(7). By Theorem 3.3, and ([6, Proposition 7])
it vio. By ([6, Proposition 28]),
is obus.
(4) (1)
27]). q.e.d.
Here we co
.PFPTKF Now if AS is a P-regu
t is obvious that S
Wlar right Rees
factor S-act, then i
A
satisfies Condi-
tion
P, also by assumption S
A
is,KF and so S
ees factor acts implies other properties.
Theorem 3.3. Let S be a monoid and T
A
is W q.e.d.
Corollary 3.10.
.PF For any monoid S the following state-
m
ty of S-acts implied by freeness. Thell P-regular
right Rees factor S-acts satisfy property

U if and only
if S is not right reversible or S
satisfies operty (U).
Proof. Suppose that S is ht reversible. By (1) of
ents are equivalent:
1) S
is .WPF
pr rig
Theorem 2.1, SS
SS
atisfies pr
 is P-regular, and so by as-
sumption S
soperty

U.
Conversel, suppose yS
SK is egP-rular for the right
ideal S
K
of S. Then thre two cases as follows:
Cas. S
ere a
e 1
K
S. Then SS
SK  is P-regular, and
S is right rso by (1) ofm 2.1, eversible.
Thus by assumption
Theore
SS
SK
satisfies property (U).
Case 2. S
K
is a prideal of S. By Theo-oper t righ
rem 3.1, 1K, and so
SSS
SK S. Ths uS
SK is
free, and so satisfies property
. q.e.
on
U
men all P-regu-
la ac
from Teorem 3.3, and ([2, I, 5.23]).
q. ollary 3.8. Let S be a monoid. Then all P-regular
rig
2, III, 17.2 ]).
q. ollary 3.9. Let S be a monoid. Then all P-regular
rig
([2, III, 14
q. orem 3.4. For any monoid S the following state-
mt Rees factor S-acts are WPF.
ke
S
7) S is not right reveev,zS ker
d
Corollary 3.7. Let S be aoid. Th
r right Rees factor S-ts are free if and only if S is not
right reversible or

1S.
Proof. It followsh
e.d.
Cor
ht Rees factor S-acts are projective if and only if S is
not right reversible or S contains a left zero.
Proof. It follows from Theorem 3. 3, and ([
e.d.
Cor
ht Rees factor S-acts are strongly flat if and only if S is
not right reversible or S is left collapsible.
Proof. It follows from Theorem 3. 3, and.3]).
e.d
The
ents are equivalent:
1) All P-regular righ
2) All P-regular right Rees factor S-acts are WKF.
3) All P-regular right Rees factor S-acts are PWKF
4) All P-regular right Rees factor S-acts are TKF.
5) S is not right reversible or S is weakly left collapsible.
6) S is not right reversible or for every left ideal I of S,
rf is connected for every homomorphism
:.
S
fI S rsible or for ery
z
2) S
is .WK F
S ht revble and weakly left collapsible.
S
3) is rigersi
4) is right reversible and for every left ideal
I
of
Sr
fI
5) S is rit reversible and for every ,zS ker
, kef is connected for every homomorphism
:.
SS
S
gh
z
is ne (2) is obvious.
concted as a left S-act.
Proof. Implication (1)
(1)
(3). It is obvioby ([6, Corollary us 24]).
(3)
(4)
(5). It is obvious by Theorem 3.4.
(3)
(4). I o bvious by ([6, Proposition 8]). q.e.dt is.
lla
ThCorory 3.11. Let S be a right reversible monoid.
en S
is WPF if ad only if S
is .TKF
ProoIt is ious that every PF rS
n
f. obvWight -act is
T.KF If S
is ,TKF then by ([6osition 7]), for
zS , Prop
every ,
ker
z
is
lary connected as a left S-act, and so
by Corol 3.10 S
is .WPF q.e.d.
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